排行榜 隐身报错处理
This commit is contained in:
parent
9fc19ebe6c
commit
c7ff94feb0
@ -152,7 +152,7 @@ public class RankingListQryExe {
|
|||||||
|
|
||||||
// 从排行榜列表中查找当前用户
|
// 从排行榜列表中查找当前用户
|
||||||
Optional<RankingActivityRecordCO> userInList = rankingList.stream()
|
Optional<RankingActivityRecordCO> userInList = rankingList.stream()
|
||||||
.filter(record -> record.getUserId().equals(cmd.getReqUserId()))
|
.filter(record -> cmd.getReqUserId().equals(record.getUserId()))
|
||||||
.findFirst();
|
.findFirst();
|
||||||
|
|
||||||
if (userInList.isPresent()) {
|
if (userInList.isPresent()) {
|
||||||
|
|||||||
Loading…
x
Reference in New Issue
Block a user